Empirical Formula Calculator
Find the simplest whole number formula of a compound from element masses or percentages.
Enter one element per line as symbol and mass, for example: C 40.0. Use grams or percentages, the math is the same.
Empirical Formula
Mole Steps
| Element | Amount | Atomic mass | Moles | Divide by smallest |
|---|
How It Works
Divide each mass by the atomic mass to get moles. Divide every mole value by the smallest one. Round to whole numbers. Those whole numbers are the subscripts in the empirical formula.
Worked example, glucose data: C 40.0%, H 6.7%, O 53.3%. Moles: 40.0 / 12.011 = 3.33 mol C, 6.7 / 1.008 = 6.65 mol H, 53.3 / 15.999 = 3.33 mol O. Divide by the smallest (3.33): C 1, H 2, O 1. The ratio is 1:2:1, so the empirical formula is CH2O.
Atomic Masses Used (IUPAC standard atomic weights)
Hydrogen (H)
1.008
Carbon (C)
12.011
Nitrogen (N)
14.007
Oxygen (O)
15.999
Sodium (Na)
22.990
Magnesium (Mg)
24.305
Sulfur (S)
32.06
Chlorine (Cl)
35.45
Calcium (Ca)
40.078
Iron (Fe)
55.845
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